document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395231>Question 395231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the polynomial below, -2 is a zero. <BR>\n" );
document.write( "f(x)=x^3+8x^2+14x+4<BR>\n" );
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document.write( "Express f(x) as a product of linear factors.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280506 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The algebra will take a while, but I'll get you started:\r<BR>\n" );
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document.write( "If r is a root of some polynomial f(x), then x-r is a factor of the polynomial. Since -2 is a root, then x+2 is a factor. You can divide f(x) by x+2 either using long division or synthetic division to obtain a quadratic. Once you have the quadratic, find the other two roots, and then you can write the polynomial as a product of linear factors. </SPAN>\n" );
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