document.write( "Question 5451: i need to write y+4=-2/3(x-9) in standard form.
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Algebra.Com's Answer #2805 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Start by multiplying both sides by the denominator which is 3:\r
\n" ); document.write( "\n" ); document.write( "\"y%2B4=%28-2%2F3%29%2A%28x-9%29\"
\n" ); document.write( "\"3%2A%28y%2B4%29=3%2A%28-2%2F3%29%2A%28x-9%29\"
\n" ); document.write( "\"3y+%2B+12+=+-2%28x-9%29\"
\n" ); document.write( "\"3y+%2B+12+=+-2x+%2B+18\"\r
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\n" ); document.write( "\n" ); document.write( "Add +2x and - 12 to each side:
\n" ); document.write( "\"2x+%2B+3y+%2B+12+-+12+=+-2x+%2B+2x+%2B+18+-+12\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+3y+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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