document.write( "Question 393984: One solution is 14% acid and another is 19% acid. How much of each solution is needed to make 100 mL solution that is 15% acid? \n" ); document.write( "
Algebra.Com's Answer #280481 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 0.14x + 0.19(100 - x) = 0.15*100 \n" ); document.write( "==> 0.14x + 19 - 0.19x = 15 \n" ); document.write( "==>-0.05x = -4 \n" ); document.write( "==> x = 80 ml of the 14% acid solution, and \n" ); document.write( "100 - x = 20 ml of the 19% acid solution. \n" ); document.write( " |