document.write( "Question 395146: 1. the sum of the digits f a two-digit number is 11. when the digits are reversed, the new number is increased by 20 which is twice the original number. find the original number.\r
\n" ); document.write( "\n" ); document.write( "2. the units digit of a two-digit number is 3 less than its tens digit. if the number is divided by the sum of its digits, the quotient is 6 and the remainder is 8. find the number.\r
\n" ); document.write( "\n" ); document.write( "pls help me! \n" ); document.write( "
Algebra.Com's Answer #280474 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
The solution to the first problem provided by another tutor is correct. The solution to the second problem has an error.

\n" ); document.write( "2. the units digit of a two-digit number is 3 less than its tens digit. if the number is divided by the sum of its digits, the quotient is 6 and the remainder is 8. find the number.\r
\n" ); document.write( "\n" ); document.write( "The proper equations which express this are:
\n" ); document.write( "u = t-3
\n" ); document.write( "\"%2810t%2Bu%29%2F%28t%2Bu%29+=+6+%2B+8%2F%28t%2Bu%29\"

\n" ); document.write( "We can eliminate the fractions in the second equation if we multiply both sides of the equation by (t+u):
\n" ); document.write( "\"%28%2810t%2Bu%29%2F%28t%2Bu%29%29%28t%2Bu%29+=+%286+%2B+8%2F%28t%2Bu%29%29%28t%2Bu%29\"
\n" ); document.write( "which simplifies as follows:
\n" ); document.write( "10t + u = 6*(t+u) + 8
\n" ); document.write( "10t + u = 6t + 6u + 8
\n" ); document.write( "Substituting t-3 for u we get:
\n" ); document.write( "10t + (t-3) = 6t + 6(t-3) + 8
\n" ); document.write( "which simplifies to:
\n" ); document.write( "11t - 3 = 6t + 6t - 18 + 8
\n" ); document.write( "11t - 3 = 12t - 10
\n" ); document.write( "Subtracting 11t from each side:
\n" ); document.write( "-3 = t - 10
\n" ); document.write( "Adding 10 to each side:
\n" ); document.write( "7 = t
\n" ); document.write( "This makes u = 7-3 or 4.
\n" ); document.write( "The original number is 74. \n" ); document.write( "
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