document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395125>Question 395125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne has $2.35 in nickels and dimes, 27 coins in all. how many nickels does she have? put as an equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280437 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If N = the number of nickels ($0.05) and D = the number of dimes ($0.10), then:<BR>\n" );
document.write( "1) N+D = 27 \"Anne has...27 coins in all.\"<BR>\n" );
document.write( "2) ($0.05)N+($0.10)D = $2.35 \"Anne has $2.35 in nickels and dimes,...\"<BR>\n" );
document.write( "Rewrite equation 1) as:<BR>\n" );
document.write( "1a) N = 27-D and substitute this for N in equation 2).<BR>\n" );
document.write( "2a) ($0.05)(27-D)+($0.10)D = $2.35 Simplify and solve for D.<BR>\n" );
document.write( "2b) 1.35-0.05D+0.1D = 2.35<BR>\n" );
document.write( "2c) 0.05D = 1.00<BR>\n" );
document.write( "2d) D = 20 and N = 27-20 = 7<BR>\n" );
document.write( "Anne has 7 nickels. </SPAN>\n" );
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