document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395132>Question 395132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please can you help me with the equation to solve the following word problem:<BR>\n" );
document.write( "A Chemist is making a new cleaning product by mixing 2 solutions. How many litres of a 35% solution should be added to the 15% solution  to obtain 8 litres of a cleaning solution with 20% concentration?<BR>\n" );
document.write( "Thanking you in advance for your assistance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280426 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number litres of the 35% solution then (8-x) will be the required number of litres of the 15% solution. <BR>\n" );
document.write( "Note that x + (8-x) = 8, so, after converting the percentages to their decimal equivalents, we have...<BR>\n" );
document.write( "0.35x+0.15(8-x) = 0.2(8) Simplify and solve for x.<BR>\n" );
document.write( "0.35x+1.2-0.15x = 1.6<BR>\n" );
document.write( "0.2x = 0.4<BR>\n" );
document.write( "x = 2.<BR>\n" );
document.write( "The chemist will need to add 2 litres of the 35% solution to (8-2=6) 6 litres of the 15% solution to obtain 8 litres of 20% solution.<BR>\n" );
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