document.write( "Question 395082: An airplane takes 6 hours to travel a distance of 5400km against the wind. The return trip takes 5 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind? \r
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Algebra.Com's Answer #280403 by stanbon(75887)\"\" \"About 
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An airplane takes 6 hours to travel a distance of 5400km against the wind. The return trip takes 5 hours with the wind. What is the rate of the plane in still air and what is the rate of the wind?
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\n" ); document.write( "Against wind DATA:
\n" ); document.write( "distance = 5400 km ; time = 6 hrs ; rate = 5400/6 = 900 km/h
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\n" ); document.write( "With wind DATA:
\n" ); document.write( "distance = 5400 km ; time = 5 hrs ; rate = 5400/5 = 1080 km/h
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\n" ); document.write( "Equations:
\n" ); document.write( "Let p be plane speed in still air.
\n" ); document.write( "Let w be wind speed.
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\n" ); document.write( "p-w = 900
\n" ); document.write( "p+w = 1000
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\n" ); document.write( "Add:
\n" ); document.write( "2p = 1900
\n" ); document.write( "p = 950 km/h
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\n" ); document.write( "Then w = 50 km/h
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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