document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395086>Question 395086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car dealership interviewed every driver who came onto their lot on Tuesday. This produced the following results: there were 34 people who owned trucks and 54 people who owned cars. If 12 people owned both a truck and a car and 8 people owned neither, how many people were interviewed?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280395 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280395\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let T = number truck owners<BR>\n" );
document.write( "let C=number of car owners<BR>\n" );
document.write( "let B=number who own both<BR>\n" );
document.write( "let N=number who own neither<BR>\n" );
document.write( "===<BR>\n" );
document.write( "given T=34, C=54, B=12, N=8<BR>\n" );
document.write( "Total interviewed =34+54-12+8=84<BR>\n" );
document.write( "--<BR>\n" );
document.write( "subtract B=12 because in counting T and C the B is counted twice.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );