document.write( "Question 43003: The length of a rectangle is 8 in. more than twice it's width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #28033 by pwac(253)\"\" \"About 
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Let w = width\r
\n" ); document.write( "\n" ); document.write( "So length(l) is 2w+8\r
\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle is 2l + 2w
\n" ); document.write( "In this case:
\n" ); document.write( "2(2w+8)+ 2w = 64. multiply out bracket on left
\n" ); document.write( "4w+16+2w = 64
\n" ); document.write( "6w+16 = 64 subtract 16 from both sides
\n" ); document.write( "6w = 48 divide both sides by 6
\n" ); document.write( "w = 8
\n" ); document.write( "Width of rectangle is 8 inches\r
\n" ); document.write( "\n" ); document.write( "Pete
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