document.write( "Question 394986: How do I draw a graph for y = 3 x + 1 \n" ); document.write( "
Algebra.Com's Answer #280328 by MathLover1(20850)\"\" \"About 
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Solved by pluggable solver: Graphing Linear Equations

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\n" ); document.write( " \"1%2Ax%2B2%2Ay=3\"Start with the given equation
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\n" ); document.write( " \"2%2Ay=3-1%2Ax\" Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%281%2F2%29%283-1%2Ax%29\" Multiply both sides by \"1%2F2\"
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\n" ); document.write( " \"y=%281%2F2%29%283%29-%281%2F2%29%281%29x%29\" Distribute \"1%2F2\"
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\n" ); document.write( " \"y=3%2F2-%281%2F2%29x\" Multiply
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\n" ); document.write( " \"y=%28-1%2F2%29%2Ax%2B3%2F2\" Rearrange the terms
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\n" ); document.write( " \"y=%28-1%2F2%29%2Ax%2B3%2F2\" Reduce any fractions
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\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=-1%2F2\" (the slope) and \"b=3%2F2\" (the y-intercept)
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\n" ); document.write( " So to graph this equation lets plug in some points
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\n" ); document.write( " Plug in x=-9
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\n" ); document.write( " \"y=%28-1%2F2%29%2A%28-9%29%2B3%2F2\"
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\n" ); document.write( " \"y=9%2F2%2B3%2F2\" Multiply
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\n" ); document.write( " \"y=12%2F2\" Add
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\n" ); document.write( " \"y=6\" Reduce
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\n" ); document.write( " So here's one point (-9,6)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-7
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\n" ); document.write( " \"y=%28-1%2F2%29%2A%28-7%29%2B3%2F2\"
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\n" ); document.write( " \"y=7%2F2%2B3%2F2\" Multiply
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\n" ); document.write( " \"y=10%2F2\" Add
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\n" ); document.write( " \"y=5\" Reduce
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\n" ); document.write( " So here's another point (-7,5). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=%28-1%2F2%29%2Ax%2B3%2F2\" through the points (-9,6) and (-7,5)
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\n" ); document.write( " So from the graph we can see that the slope is \"-1%2F2\" (which tells us that in order to go from point to point we have to start at one point and go down -1 units and to the right 2 units to get to the next point), the y-intercept is (0,\"1.5\") ,or (0,\"3%2F2\"), and the x-intercept is (\"3\",0) . So all of this information verifies our graph.
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\n" ); document.write( " We could graph this equation another way. Since \"b=3%2F2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"3%2F2\").
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\n" ); document.write( " So we have one point (0,\"3%2F2\")
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\n" ); document.write( " Now since the slope is \"-1%2F2\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"3%2F2\"), we can go down 1 units
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\n" ); document.write( " and to the right 2 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=%28-1%2F2%29%2Ax%2B3%2F2\"
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\n" ); document.write( " So this is the graph of \"y=%28-1%2F2%29%2Ax%2B3%2F2\" through the points (0,1.5) and (2,0.5)
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