document.write( "Question 394937: Inequalities ; If xy=25 find the least possible value for x+y, if both x and y are positive? \n" ); document.write( "
Algebra.Com's Answer #280286 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If xy=25 find the least possible value for x+y, if both x and y are positive? \n" ); document.write( "--- \n" ); document.write( "x = 25/y \n" ); document.write( "--- \n" ); document.write( "Substitute to get: \n" ); document.write( "Sum = (25/y)+y \n" ); document.write( "--- \n" ); document.write( "Sum = (25+y^2)/y \n" ); document.write( "---- \n" ); document.write( "Find the derivative: \n" ); document.write( "S' = [y(2y)-(25+y^2)]/y^2 \n" ); document.write( "-- \n" ); document.write( "S' =[y^2-25]/y^2 \n" ); document.write( "--- \n" ); document.write( "S' = 1-[(25)/y^2] \n" ); document.write( "---- \n" ); document.write( "To find min/max solve S' = 0 \n" ); document.write( "1-[(25/y^2)] = 0 \n" ); document.write( "(25/y^2) = 1 \n" ); document.write( "y^2 = 25 \n" ); document.write( "y = 5 \n" ); document.write( "--- \n" ); document.write( "Substitute xy = 25 \n" ); document.write( "If y = 5, then x = 5 \n" ); document.write( "--- \n" ); document.write( "So, the minimum sum is 5+5 = 10 \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |