document.write( "Question 42963: One day, the temperature at 2:00 A.M. was 43F, and by 3:00 the temperature was 56 F. What was the hourly rate of temperature change? \n" ); document.write( "
Algebra.Com's Answer #28026 by Nate(3500)\"\" \"About 
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If you mean 3:00 A.M.
\n" ); document.write( "(change of temperature)/(change of time)
\n" ); document.write( "(56 - 43)/(3 - 2)
\n" ); document.write( "(13)/(1) = 13
\n" ); document.write( "13 degrees per hour
\n" ); document.write( "If you mean 3:00 P.M.
\n" ); document.write( "(change of temperature)/(change of time)
\n" ); document.write( "(56 - 43)/(15 - 2)
\n" ); document.write( "(13)/(13) = 1
\n" ); document.write( "1 degree per hour
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