document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394898>Question 394898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this is a d=rt problem Tina get a head start and leave work traveling at 45 mph three hour later Tim leaves work on the same road at 65 mph.how many mile will Tim pass Tina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280258 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is a d=rt problem Tina get a head start and leave work traveling at 45 mph three hour later Tim leaves work on the same road at 65 mph.how many mile will Tim pass Tina?\r<BR>\n" );
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document.write( "Tina 45 mph<BR>\n" );
document.write( "leaves 3 hours early <BR>\n" );
document.write( "so when Tim starts she is 45 * 3 = 135 miles ahead.<BR>\n" );
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document.write( "Tim speed = 65mph<BR>\n" );
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document.write( "the catch up speed = 65-45 20 mph<BR>\n" );
document.write( "catch up distance = 135 miles<BR>\n" );
document.write( "Time taken by Tim  to catch up = 135/20 = 6.75 hours<BR>\n" );
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document.write( "Tim speed = 65 mph<BR>\n" );
document.write( "time catch up = 6.75 hours<BR>\n" );
document.write( "Distance he meets = 6.75 * 65=438.7 km<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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