document.write( "Question 394530: A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid ounces of 25% alcohol solution. How many fluid ounces of each are needed? \n" ); document.write( "
Algebra.Com's Answer #280173 by ankor@dixie-net.com(22740)\"\" \"About 
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A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid
\n" ); document.write( " ounces of 25% alcohol solution.
\n" ); document.write( " How many fluid ounces of each are needed?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 35% solution
\n" ); document.write( "then
\n" ); document.write( "(60-x) = amt of 20% solution
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation based on percent alcohol
\n" ); document.write( ".35x + .20(60-x) = .25(60)
\n" ); document.write( ".35x + 12 - .20x = 15
\n" ); document.write( ".35x - .20x = 15 - 12
\n" ); document.write( ".15x = 3
\n" ); document.write( "x = \"3%2F.15\"
\n" ); document.write( "x = 20 0z of 35% solution required
\n" ); document.write( "then
\n" ); document.write( "60 - 20 = 40 oz of 20% solution required
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( ".35(20) + .20(60-20) = .25(60)
\n" ); document.write( "7 + 8 = 15
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