document.write( "Question 394530: A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid ounces of 25% alcohol solution. How many fluid ounces of each are needed? \n" ); document.write( "
Algebra.Com's Answer #280173 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A 20% alcohol solution is mixed with a 35% alcohol solution to obtain 60 fluid \n" ); document.write( " ounces of 25% alcohol solution. \n" ); document.write( " How many fluid ounces of each are needed? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 35% solution \n" ); document.write( "then \n" ); document.write( "(60-x) = amt of 20% solution \n" ); document.write( ": \n" ); document.write( "A typical mixture equation based on percent alcohol \n" ); document.write( ".35x + .20(60-x) = .25(60) \n" ); document.write( ".35x + 12 - .20x = 15 \n" ); document.write( ".35x - .20x = 15 - 12 \n" ); document.write( ".15x = 3 \n" ); document.write( "x = \n" ); document.write( "x = 20 0z of 35% solution required \n" ); document.write( "then \n" ); document.write( "60 - 20 = 40 oz of 20% solution required \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( ".35(20) + .20(60-20) = .25(60) \n" ); document.write( "7 + 8 = 15 \n" ); document.write( " |