document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394323>Question 394323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would appreciate help with the following logarithmic equation. I need to solve out to two decimal places.\r<BR>\n" );
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document.write( "log(x+3)+log(x-2)= log14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280172 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(x+3)+log(x-2)= log14<BR>\n" );
document.write( "use logarithm rule for multiplication<BR>\n" );
document.write( "log(x+3)(x-2) =log14<BR>\n" );
document.write( "(x+3)(x-2)=14<BR>\n" );
document.write( " x^2+x-6=14<BR>\n" );
document.write( " x^2+x-20=0<BR>\n" );
document.write( "solve by factoring<BR>\n" );
document.write( "(x+5)(x-4)=0<BR>\n" );
document.write( "ans: x=-5(reject,logarithm>0)<BR>\n" );
document.write( "     x=4<BR>\n" );
document.write( "check:<BR>\n" );
document.write( "log(x+3)+log(x-2)= log14<BR>\n" );
document.write( "log7+log2=log14<BR>\n" );
document.write( ".8451+.3010=1.146<BR>\n" );
document.write( "      1.146=1.146 </SPAN>\n" );
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