document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394776>Question 394776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using only 4 fours and any mathematical signs or symbols (EX. +, -, Sq. root, /, *, i) write an equation that equals 33. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280134 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm a little unsure if there is a way to get 33 using four 4's and standard arithmetic operations. A simple way uses six 4's:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A4+%2B+4%2A4+%2B+4%2F4+=+33 ALIGN=MIDDLE  ALT=\"4%2A4+%2B+4%2A4+%2B+4%2F4+=+33\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The closest I got involved five 4's:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%21+%2B+%28sqrt%284+-+4%2F4%29%29%5E4+=+33 ALIGN=MIDDLE  ALT=\"4%21+%2B+%28sqrt%284+-+4%2F4%29%29%5E4+=+33\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Play around with it, see if you can do it using four of them. </SPAN>\n" );
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