document.write( "Question 42968: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers? \n" ); document.write( "

Algebra.Com's Answer #28013 by jmg(22) $\"\"$ $\"About$

You can put this solution on YOUR website!
It talks about an integer and the next consecutive integer
\n" ); document.write( "So you would let the integer be n, and the next consective would be 1 more than that number so it would be (n+1)\r
\n" ); document.write( "\n" ); document.write( "Using the question:
\n" ); document.write( "If one-half of one integer is SUBTRACTED FROM three-fifths of the next, the difference is 3. \r
\n" ); document.write( "\n" ); document.write( "Just change the words to numbers and symbols. \r
\n" ); document.write( "\n" ); document.write( "1/2(n) is SUBTRACTED FROM 3/5(n+1) = 3 , so you would actually write it\r
\n" ); document.write( "\n" ); document.write( "3/5(n + 1) - 1/2(n) = 3 Distribute
\n" ); document.write( "3/5(n) + 3/5 - 1/2(n) = 3 Combine your like terms the 3/5 and 1/2 n
\n" ); document.write( "1/10(n) + 3/5 = 3 Move the 3/5 to the other side
\n" ); document.write( "1/10(n) = 12/5 Multiply by the reciprocal of 1/10, which would be 10/1 in order to eliminate the fraction in front of the n.
\n" ); document.write( "This gives you n = 24, which is the integer, so the next consecutive integer would be 24 + 1 = 25.\r
\n" ); document.write( "\n" ); document.write( "So your numbers are 24 and 25
\n" ); document.write( "Hope this helps \n" ); document.write( "

\n" );