Algebra.Com's Answer #280126 by stanbon(75887)![\"\"](\"/images/stars/stars-13.gif\")  
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Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic fuction, and graph the function.
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document.write( "f(x)=3x^2-12x+16
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document.write( "Vertex occurs at x = -b/(2a) = 12/(6) = 2
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document.write( "f(2) = 3*2^2-12*2+16 = 12-24+16 = 4\r
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document.write( "The vertex is (2,4) (Type an ordered pair.)\r
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document.write( "The line of symmetry is x=2
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document.write( "A. y=4
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document.write( "B. x=2
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document.write( "C. x=-2
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document.write( "D. y=-4\r
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document.write( "The maximum/minimum of f(x) is (2,4).\r
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document.write( "Is the value, f(2)=4 a minimum or a maximum?
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document.write( "Minimum
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document.write( "Graph.
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document.write( "Cheers,
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document.write( "Stan H. \n" );
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