document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42928>Question 42928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 over c^2d + 7 over cd^3=\r<BR>\n" );
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document.write( "unlike denominators </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28008 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here we need to convert each to the lowest common denominator, which is c^2d^3, so we get\r<BR>\n" );
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document.write( "2 / c^2d + 7 / cd^3 =<BR>\n" );
document.write( "2d^2 / c^2d^3 + 7c / c^2d^3 =<BR>\n" );
document.write( "(2d^2 + 7c) / c^2d^3 </SPAN>\n" );
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