document.write( "Question 394723: Sandy and Claude are playing a game in which there are 5 tiles in a bag, numbered 1 through 5. The game is played by the players taking turns pulling out a tile without replacing it. A player wins if they pull out the tile numbered \"3\". If Sandy goes first, what is the probability that she will win?
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document.write( "choose the answer and explain the reason to choose your response
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document.write( "50%
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document.write( "45%
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document.write( "75%
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document.write( "60% \n" );
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Algebra.Com's Answer #280056 by jrfrunner(365)![]() ![]() You can put this solution on YOUR website! p(sandy wins/she goes first)=0.6 \n" ); document.write( "-- \n" ); document.write( "reasoning \n" ); document.write( "on her first try, she has 1/5 chance of getting the \"3\" tile and wins \n" ); document.write( "if she does not get the \"3\" tile, then clause has 3/4 of not getting the \"3\" tile since there are only 4 tles left and the game can continue. \n" ); document.write( "- \n" ); document.write( "On Sandy's second try, there are only 3 tiles left and for Sandy to get a second chance to win, she must of failed the first time 4/5 chance and Claude must of failed 3/4 chance and for Sandy to win in the second try she has 1/3 chance so Sandy can win on the second try with 4/5*3/4*1/3=1/5 \n" ); document.write( "-- \n" ); document.write( "If Sandy does not win of the second, she gets a third try if she failed on the first and Claude failed oh his first and sandy failed on her second and cluade failed on his second and finally Sandy tries a 3rd time. This can happen by Sandy failing on first 4/5 chance, Claude failing first 3/4 chance, sandy failing on second 2/3 chance and claude failing on his second with 1/2 chance \n" ); document.write( "or 4/5*3/4*2/3*1/2=1/5 \n" ); document.write( "after this there are no more tiles \n" ); document.write( "- \n" ); document.write( "So sandy wins by going first if she wins on the first try, or second try or 3rd try = 1/5+1/5+1/5=3/5=0.6 \n" ); document.write( " \n" ); document.write( " |