document.write( "Question 394704: THE SUM OF THE SQUARES OF TWO CONSECUTIVE POSITIVE INTEGERS IS 41
\n" ); document.write( "41=n^2(n+1)^2
\n" ); document.write( "n^2+n^2+2n-40=0
\n" ); document.write( "n^2+2n-40=0
\n" ); document.write( "factor out 2
\n" ); document.write( "n^2+n-20=0
\n" ); document.write( "I tried different factors of -20 (n+1)(n-20)=-19; (n+2)(n-10)=-8
\n" ); document.write( "(n+10)(n-2)=8 (n+20)(n-1)=19 i know the answers are supposed to be 2 and 4 so I know I am wrong but where? \n" ); document.write( "

Algebra.Com's Answer #280038 by richard1234(7193) $\"\"$ $\"About$

You can put this solution on YOUR website!
-20 is also equal to 4*(-5) or (-4)*5. You should factor it as\r
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\n" ); document.write( "\n" ); document.write( " $\"%28n+-+4%29%28n+%2B+5%29+=+0\"$ in which the values of n are 4 and -5. Since the integers are positive, n = 4. \n" ); document.write( "

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