document.write( "Question 394695: If the line y=A+B(x-6) is perpendicular to the line y=2x and it contains the point (1,10), what are the values of A and B? \n" ); document.write( "
Algebra.Com's Answer #280034 by nerdybill(7384)\"\" \"About 
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If the line y=A+B(x-6) is perpendicular to the line y=2x and it contains the point (1,10), what are the values of A and B?
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\n" ); document.write( "slope of
\n" ); document.write( "y=2a
\n" ); document.write( "is 2
\n" ); document.write( "a line perpendicular must have a \"negative reciprocal\"
\n" ); document.write( "2m = -1
\n" ); document.write( "m = -1/2 (slope of our line)
\n" ); document.write( ".
\n" ); document.write( "y=A+B(x-6)
\n" ); document.write( "y=A+Bx-6B
\n" ); document.write( "y=Bx+A-6B
\n" ); document.write( "y=Bx+(A-6B)
\n" ); document.write( "the above is in \"slope-intercept\" form
\n" ); document.write( "where B is the slope
\n" ); document.write( "(A-6B) is the y-intercept
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\n" ); document.write( "We found our slope above as -1/2 and we also were given one point (1,10) plug it in:
\n" ); document.write( "y=Bx+(A-6B)
\n" ); document.write( "now we know B=-1/2
\n" ); document.write( "10=(-1/2)(1)+(A-6(-1/2))
\n" ); document.write( "10=(-1/2)+(A+3)
\n" ); document.write( "10=(-1/2)+A+3
\n" ); document.write( "7=(-1/2)+A
\n" ); document.write( "7.5 = A
\n" ); document.write( ".
\n" ); document.write( "Answer:
\n" ); document.write( "B= -.5
\n" ); document.write( "A= 7.5\r
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