document.write( "Question 394680: Paul is 15 years younger then Ken. In 5 years Ken will be twice as old as Paul. How old will Paul be in four years? \n" ); document.write( "
Algebra.Com's Answer #280033 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Paul is 15 years younger then Ken
\n" ); document.write( "Let x and (x-15) represent Ken and Paul's ages NOW respectively
\n" ); document.write( "Write as we Read*** in five years...
\n" ); document.write( " [x+5] = 2[(x-15) + 5]
\n" ); document.write( "solving for x
\n" ); document.write( " x + 5 = 2x - 20
\n" ); document.write( " 25 = x, Ken's age now, Paul is now 10. Paul be in four years will be 14.\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***in five years...
\n" ); document.write( " 30 = 2*15 \n" ); document.write( "
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