document.write( "Question 394612: if tanA+secA= 3 then find tha value of sinA. \n" ); document.write( "
Algebra.Com's Answer #280015 by richard1234(7193)\"\" \"About 
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Rewrite everything in terms of sin(A) and cos(A) to get\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28A%29%2Fcos%28A%29+%2B+1%2Fcos%28A%29+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28sin%28A%29+%2B+1%29%2Fcos%28A%29+=+3\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28A%29+%2B+1+=+3+cos+%28A%29\" I'll rewrite \"cos%28A%29\" as \"sqrt%281-sin%5E2%28A%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28A%29+%2B+1+=+3sqrt%281+-+sin%5E2+%28A%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Squaring both sides,\r
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\n" ); document.write( "\n" ); document.write( "\"sin%5E2+%28A%29+%2B+2sin%28A%29+%2B+1+=+9+-+9+sin%5E2+%28A%29\" Let \"u+=+sin%5E2+%28A%29\". It is easy to see that we can now obtain a quadratic:\r
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\n" ); document.write( "\n" ); document.write( "\"10u%5E2+%2B+2u+-+8+=+0\" --> \"5u%5E2+%2B+u+-+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"u+=+%28-1+%2B-+sqrt%281+%2B+80%29%29%2F10+=+%28-1+%2B-+9%29%2F10\" = -1 or 4/5. These values are between -1 and 1 inclusive, so these are the two possible values for sin(A).\r
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