document.write( "Question 394614: I need the last two digits from the following numbers 11^2011. I need all work t be shown please, so I can fugure out how to do my other problems, PLEASE and super huge thank you!! \n" ); document.write( "
Algebra.Com's Answer #280001 by Alan3354(69443)\"\" \"About 
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I need the last two digits from the following numbers 11^2011.
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\n" ); document.write( "The last 2 digits are cyclic, and are equal to the exponent modulo 10.
\n" ); document.write( "For exponents from 1 to 10, they are:
\n" ); document.write( "11
\n" ); document.write( "21
\n" ); document.write( "31
\n" ); document.write( "41
\n" ); document.write( "51
\n" ); document.write( "61
\n" ); document.write( "71
\n" ); document.write( "81
\n" ); document.write( "91
\n" ); document.write( "01
\n" ); document.write( "Then they repeat.
\n" ); document.write( "2011/10 = 201 remainder 1, so the last 2 digits are the same as 11^1
\n" ); document.write( "= 11.\r
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