document.write( "Question 394643: A rectangular garden has dimensions of 15 feet by 9 feet. A gravel path of equal width is to be built around the gard. How wide can the path be if there is enough gravel for 432 ft^2? \n" ); document.write( "

Algebra.Com's Answer #279995 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x represent the width of the walk. Garden has an Area= 15*9 = 135 ft^2
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document.write( "Question states***
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document.write( " (15+2x)(9+2x) - 135ft^2 = 432ft^2, the area of the path.
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document.write( "solving for x
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document.write( " 135 + 48x + 4x^2 - 135 = 432
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document.write( "    4x^2 + 48x - 432 = 0
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document.write( "     x^2 + 12x - 108 = 0
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document.write( "factoring or using quadratic formula  
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document.write( "   (x + 18)(x-6) = 0   |tossing out negative solution for length
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document.write( "            x = 6ft, the width of the walk \n" );
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