document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394626>Question 394626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8.A computer assembling company receives 24% of parts from supplier X, 36% of parts from supplier Y, and the remaining 40% of parts from supplier Z. Five percent of parts supplied by X, ten percent of parts supplied by Y, and six percent of parts supplied by Z are defective. If an assembled computer has a defective part in it, what is the probability that this part was received from supplier Z? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279978 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(Z|def) = P(def AND Z)/P(def)\r<BR>\n" );
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document.write( "=(P(def|Z)*P(Z))/(P(def|X)*P(X) + P(def|Y)*P(Y) + P(def|Z)*P(Z))\r<BR>\n" );
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document.write( "= 0.06*0.40/(0.05*0.24+0.10*0.36+0.06*0.40) = 0.024/0.072 = 1/3 </SPAN>\n" );
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