document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394645>Question 394645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill can row 3mph in still water.  It takes him 3 hours 36 minutes to go 3 miles upstream and return.  Find the speed of the current. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279974 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill can row 3mph in still water. It takes him 3 hours 36 minutes to go 3 miles upstream and return. Find the speed of the current.\r<BR>\n" );
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document.write( "change 3 hours and 36 minutes to 3 and 3/5 of an hour = 3.6 hour<BR>\n" );
document.write( "let x=speed of current<BR>\n" );
document.write( "downstream speed = 3+x<BR>\n" );
document.write( "upstream speed = 3-x<BR>\n" );
document.write( "time=distance/speed\r<BR>\n" );
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document.write( "3/(3+x)+3/(3-x)=3.6<BR>\n" );
document.write( "3(3-x)+3(3+x) =3.6(3-x)(3+x)<BR>\n" );
document.write( "9-3x+9+3x=3.6(9-x^2)<BR>\n" );
document.write( "18=32.4-3.6x^2<BR>\n" );
document.write( "3.6x^2=32.4-18=14.4<BR>\n" );
document.write( "x^2=14.4/3.6=4<BR>\n" );
document.write( "x=sqrt(4)=2 mph or-2 mph(reject)\r<BR>\n" );
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document.write( "ans: The speed of the current is 2 mph </SPAN>\n" );
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