document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394309>Question 394309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve<BR>\n" );
document.write( "y=-x+4<BR>\n" );
document.write( "y=2x+6<BR>\n" );
document.write( "using substitution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279880 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute -x+4 into the second equation, replacing y.\r<BR>\n" );
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document.write( "-x + 4 = 2x + 6\r<BR>\n" );
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document.write( "3x = -2\r<BR>\n" );
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document.write( "x = -2/3.\r<BR>\n" );
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document.write( "Since y = -x + 4, then y = 2/3 + 4 = 14/3. Therefore the ordered pair (x,y) is (-2/3, 14/3). </SPAN>\n" );
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