document.write( "Question 394431: solve the equation for x.
\n" ); document.write( "ln(5-4x)=1
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Algebra.Com's Answer #279846 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"ln%285-4x%29=1\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5-4x=e%5E1\" Convert to exponential form\r
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\n" ); document.write( "\n" ); document.write( "\"5-4x=e\" Evaluate 'e' to the first power to get 'e'\r
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\n" ); document.write( "\n" ); document.write( "\"-4x=e-5\" Subtract \"5\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28e-5%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%28e-5%29%2F4\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=-%28e-5%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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