document.write( "Question 394157: Justin can jog to work in 3/4 of an hour. When he rides his bike, it takes him 1/3 of an hour. If he rides 12 miles per hour faster than he jogs, how far away is his work? \r
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Algebra.Com's Answer #279838 by ankor@dixie-net.com(22740)\"\" \"About 
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Justin can jog to work in 3/4 of an hour.
\n" ); document.write( "When he rides his bike, it takes him 1/3 of an hour.
\n" ); document.write( "If he rides 12 miles per hour faster than he jogs, how far away is his work?
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\n" ); document.write( "Let s = his jogging speed
\n" ); document.write( "then
\n" ); document.write( "(s+12) = his biking speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation
\n" ); document.write( "jog dist = bike dist
\n" ); document.write( "\"3%2F4\"s + \"1%2F3\"(s+12)
\n" ); document.write( "multiply by 12 to get rid of the fractions; results:
\n" ); document.write( "3(3)s = 4(s+12)
\n" ); document.write( "9s = 4s + 48
\n" ); document.write( "9s - 4s = 48
\n" ); document.write( "5s = 48
\n" ); document.write( "s = \"48%2F5\"
\n" ); document.write( "s = 9.6 mph is the jogging speed
\n" ); document.write( "then
\n" ); document.write( "(9.6+12) = 21.6 mph is the biking speed
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\n" ); document.write( "Find the distance;
\n" ); document.write( "\"3%2F4\"*9.6 = 7.2 mi
\n" ); document.write( ":
\n" ); document.write( "Check the distance, biking;
\n" ); document.write( "\"1%2F3\"*21.6 = 7.2 mi
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