document.write( "Question 394157: Justin can jog to work in 3/4 of an hour. When he rides his bike, it takes him 1/3 of an hour. If he rides 12 miles per hour faster than he jogs, how far away is his work? \r
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document.write( "Do not do any rounding.
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Algebra.Com's Answer #279838 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Justin can jog to work in 3/4 of an hour. \n" ); document.write( "When he rides his bike, it takes him 1/3 of an hour. \n" ); document.write( "If he rides 12 miles per hour faster than he jogs, how far away is his work? \n" ); document.write( ": \n" ); document.write( "Let s = his jogging speed \n" ); document.write( "then \n" ); document.write( "(s+12) = his biking speed \n" ); document.write( ": \n" ); document.write( "Write a distance equation \n" ); document.write( "jog dist = bike dist \n" ); document.write( " \n" ); document.write( "multiply by 12 to get rid of the fractions; results: \n" ); document.write( "3(3)s = 4(s+12) \n" ); document.write( "9s = 4s + 48 \n" ); document.write( "9s - 4s = 48 \n" ); document.write( "5s = 48 \n" ); document.write( "s = \n" ); document.write( "s = 9.6 mph is the jogging speed \n" ); document.write( "then \n" ); document.write( "(9.6+12) = 21.6 mph is the biking speed \n" ); document.write( ": \n" ); document.write( "Find the distance; \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Check the distance, biking; \n" ); document.write( " |