document.write( "Question 394408: Please help me with this question \r
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Algebra.Com's Answer #279833 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "So \"%28abs%283x-1%29%29%2F%28abs%281-3x%29%29=1\" when \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "Note: It turns out that \"%28abs%283x-1%29%29%2F%28abs%281-3x%29%29=1\" for any value of x (except \"x=1%2F3\") because \"abs%283x-1%29=abs%281-3x%29\" for every value of x.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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