document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394345>Question 394345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please assist me with this equation \r<BR>\n" );
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document.write( "14/x^2 + 1/x-1 = 3/x+1 I believe you would mulpliply both sides by x +1 but am not sure exactly where I am going with this. I would appreciate any help you can give me. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279802 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "You want to multiply both sides of the equation by 1 in the form of the lowest common denominator divided by itself.\r<BR>\n" );
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document.write( "Since the three denominators have no common factors, the lowest common denominator is simply the product of the three denominators.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{14}{x^2}\ +\ \frac{1}{x\ -\ 1}\right)\left(\frac{(x^2)(x\ -\ 1)(x\ +\ 1)}{(x^2)(x\ -\ 1)(x\ +\ 1)}\right)\ =\ \left(\frac{3}{x\ +\ 1}\right)\left(\frac{(x^2)(x\ -\ 1)(x\ +\ 1)}{(x^2)(x\ -\ 1)(x\ +\ 1)}\right)\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{14(x\ -\ 1)(x\ +\ 1)\ +\ (x^2)(x\ +\ 1)}{(x^2)(x\ -\ 1)(x\ +\ 1)}\ =\ \frac{3(x^2)(x\ -\ 1)}{(x^2)(x\ -\ 1)(x\ +\ 1)}\">\r<BR>\n" );
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document.write( "Now distribute, expand, and collect like terms in the numerators (verification is left as an exercise for the student -- and you had better verify it for yourself as I can and do make mistakes):\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{-2x^3\ +\ 18x^2\ -\ 14}{(x^2)(x\ -\ 1)(x\ +\ 1)}\ =\ 0\">\r<BR>\n" );
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document.write( "Now just solve the cubic.  It doesn't factor over the rationals, so you are going to either have to use the general solution of a cubic:\r<BR>\n" );
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document.write( "Check out:\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF=\"http://http://en.wikipedia.org/wiki/Cubic_function<BR>\n" );
document.write( "\">Wikipedia Cubic Function</a>\r<BR>\n" );
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document.write( "Or\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF=\"http://http://mathworld.wolfram.com/CubicFormula.html\">Wolfram Mathworld Cubic Formula</a>\r<BR>\n" );
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document.write( "But be prepared for much wailing, gnashing of teeth, and pulling of hair.\r<BR>\n" );
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document.write( "Or\r<BR>\n" );
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document.write( "Google any one of several cubic calculators.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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