document.write( "Question 42890This question is from textbook
\n" );
document.write( ": A guy wire of length 50 feet is attached to the ground and to the top of an antenna. The height of the antenna is 10 feet larger than the distance from the base of the antenna to the point where the guy wire is attached to the ground. What is the height of the antenna? \n" );
document.write( "
Algebra.Com's Answer #27978 by psbhowmick(878)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Considering triangle ABC, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here base = BC, height = AB and hypotanuse = AC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given: AC = 50 ft. \n" ); document.write( "Let BC = x feet. \n" ); document.write( "Then, AB = (x+10) feet \r \n" ); document.write( "\n" ); document.write( "[This is because height of the antenna is 10 ft larger than the distance from the base of the antenna to the point where the guy wire is attached to the ground].\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So from Pythagorus theorem we have \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( "or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So either (x + 40) = 0 or (x - 30) = 0 i.e. either x = -40 or x = 30. \n" ); document.write( "Now, 'x' being the length of a side of a triangle cannot be negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So x = 30 i.e. the distance of the base of the antenna from the point where the guy wire is attached to the ground is 30 feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the height of the antenna is (x+10) = 30+10 = 40 feet. |