document.write( "Question 394307: how do you solve
\n" ); document.write( "x=2y+2
\n" ); document.write( "2x+3y=11
\n" ); document.write( "using substitution
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Algebra.Com's Answer #279773 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x=2y%2B2\"....or....\"x+-+2y+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "now solve the system:\r
\n" ); document.write( "\n" ); document.write( "\"x+-+2y+=+2\"
\n" ); document.write( "\"2x+%2B+3y+=+11\"\r
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+-2%5Cy+=+2%2C%0D%0A++++2%5Cx+%2B+3%5Cy+=+11+%29%0D%0A++\"We'll use substitution. After moving -2*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+2+-+-2%2Ay\", or \"x+=+2%2F1+-+-2%2Ay%2F1\". Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " \"2%2A%282%2F1+-+-2%2Ay%2F1%29+%2B+3%5Cy+=+11\" and simplify: So, we know that y=1. Since \"x+=+2%2F1+-+-2%2Ay%2F1\", x=4.
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\n" ); document.write( " Answer: \"system%28+x=4%2C+y=1+%29\".
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