document.write( "Question 394149: In the year 2000 Donald was 12 and his father was 40.
\n" ); document.write( "In which year was Donald's father 8 times as old as Donald?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #279642 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
In the year 2000 Donald was 12 and his father was 40.
\n" ); document.write( "In which year was Donald's father 8 times as old as Donald?
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Let the desired year be x years before 2000 or the year 2000-x.\r\n" );
document.write( "\r\n" );
document.write( "x years before 2000 Donald was 12-x and his father was 40-x.\r\n" );
document.write( "\r\n" );
document.write( "So we want 12-x to be \"1%2F8\"th of 40-x.  To say that in algebra,\r\n" );
document.write( "\r\n" );
document.write( "          12 - x = \"1%2F8\"(40 - x)\r\n" );
document.write( "\r\n" );
document.write( "Clear of fractions by multiplying both siades by 8\r\n" );
document.write( "\r\n" );
document.write( "         96 - 8x = 8*\"1%2F8\"(40 - x)\r\n" );
document.write( "\r\n" );
document.write( "Cancel the 8 and the \"1%2F8\" and you have\r\n" );
document.write( "\r\n" );
document.write( "         96 - 8x = 40 - x\r\n" );
document.write( "             -7x = -56\r\n" );
document.write( "               x = 8\r\n" );
document.write( "\r\n" );
document.write( "So the year was 2000-x or 2000-8 or 1992, when Donald was 4 and his\r\n" );
document.write( "father was 32.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( "
\n" );