document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42873>Question 42873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3u-7  + 7u-6  =  11<BR>\n" );
document.write( "6        3\r<BR>\n" );
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document.write( "The 3u-7 is over the 6 and the 7u-6 is over the 3.  I tried it with a common denominator of 6.  The 7 and 11 is confusing me.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27963 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply everything by 6 in order to clear all fractions...we get<BR>\n" );
document.write( "3u - 7 + 2(7u - 6) = 66<BR>\n" );
document.write( "3u - 7 + 14u - 12 = 66<BR>\n" );
document.write( "17u - 19 = 66<BR>\n" );
document.write( "17u = 85<BR>\n" );
document.write( "u = 5 </SPAN>\n" );
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