document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394103>Question 394103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the answer for 3 to the power of x+1 = 2 raise to the power of 2x + 1?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279619 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the answer for 3 to the power of x+1 = 2 raise to the power of 2x + 1?\r<BR>\n" );
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document.write( "3^(x+1)=2^(2x+1)<BR>\n" );
document.write( "(x+1)log3=(2x+1)log2<BR>\n" );
document.write( "xlog3+log3=2xlog2+log2<BR>\n" );
document.write( "xlog3-2xlog2=log2-log3<BR>\n" );
document.write( "x(log3-2log2)=log2-log3<BR>\n" );
document.write( "x=(log2-log3)/(log3-2log2)<BR>\n" );
document.write( "ans:x=1.409\r<BR>\n" );
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document.write( "check:3^(1.409+1) = 2^(2*1.409+1)<BR>\n" );
document.write( "            14.105=14.104 (rounded to 3 decimal places) </SPAN>\n" );
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