document.write( "Question 394079: the diiference betwwen two numbers is 10. when eight times the smaller number is added to 40, the result is ten less than three times the larger number. find both numbers \n" ); document.write( "

Algebra.Com's Answer #279599 by pie90010(44) $\"\"$ $\"About$

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$\"x+-+y+=+10\"$
\n" ); document.write( " $\"3x+-+10+=+8y+%2B+40\"$
\n" ); document.write( "x is the larger number in this case
\n" ); document.write( "so break down the second one, so you can line it up
\n" ); document.write( " $\"3x+-+10+=+8y+%2B+40\"$
\n" ); document.write( " $\"3x+-+8y+=+50\"$
\n" ); document.write( " $\"1x+-+1y+=+10\"$
\n" ); document.write( "multiply the second equation by -3, so you can cancel the X's
\n" ); document.write( " $\"-3x+%2B+3y+=+-30\"$
\n" ); document.write( " $\"+3x+-+8y+=++50\"$
\n" ); document.write( "add them up
\n" ); document.write( " $\"-5y+=+20\"$
\n" ); document.write( " $\"y+=+-4\"$
\n" ); document.write( "now that you have y, just plug it into the original equation to get x
\n" ); document.write( " $\"x+-+y+=+10\"$
\n" ); document.write( " $\"x+-+%28-4%29+=+10\"$
\n" ); document.write( " $\"x+%2B+4+=+10%29\"$
\n" ); document.write( " $\"x+=+6\"$
\n" ); document.write( "so the solution would be
\n" ); document.write( "(6,-4)
\n" ); document.write( " \n" ); document.write( "

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