document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=394038>Question 394038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using substitution process.<BR>\n" );
document.write( "15x-9y=-3<BR>\n" );
document.write( "-5x+3y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279581 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No solutions. You can multiply the second equation by 3 to obtain\r<BR>\n" );
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document.write( "15x - 9y = -3<BR>\n" );
document.write( "-15x + 9y = -21\r<BR>\n" );
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document.write( "We see that if there is a solution (x,y), then 0 = -24 if we add the two equations. </SPAN>\n" );
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