document.write( "Question 393818: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy? \n" ); document.write( "
Algebra.Com's Answer #279549 by Alan3354(69443) You can put this solution on YOUR website! Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy? \n" ); document.write( "---------------- \n" ); document.write( "In 5 minutes, Tracy goes (36/60)*5 miles = 3 miles \n" ); document.write( "Sarah's speed relative to Tracy is 14 mi/hr (50 - 36) \n" ); document.write( "It takes 3/14 hour to catch Tracy, =~ 13 minutes. \n" ); document.write( "8:05 + 13 = 8:18\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |