document.write( "Question 393818: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy? \n" ); document.write( "
Algebra.Com's Answer #279545 by ankor@dixie-net.com(22740)\"\" \"About 
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Tracy leaves for work at 8am, traveling at 36mph.
\n" ); document.write( " Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch.
\n" ); document.write( " At what time will Sarah catch Tracy?
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\n" ); document.write( "Change 5 min to hr: 5/60 = .0833 hrs
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\n" ); document.write( "Let t = Sarah's travel time
\n" ); document.write( "then
\n" ); document.write( "(t+.0833) = Tracey's travel time
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\n" ); document.write( "When S catches T they will have traveled the same distance
\n" ); document.write( "Write a distance equation: d = speed * time
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\n" ); document.write( "50t = 36(t+.0833)
\n" ); document.write( "50t = 36t + 3
\n" ); document.write( "50t - 36t = 3
\n" ); document.write( "14t = 3
\n" ); document.write( "t = \"3%2F14\" hrs is Sarah's travel time
\n" ); document.write( "Change to minutes \"3%2F14\"*60 = 12.85 min say 13 min
\n" ); document.write( "then
\n" ); document.write( "13 + 5 = 18 min is Tracy's travel time who left at 8:00
\n" ); document.write( "S catches T at about 8:18
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\n" ); document.write( "We can check this finding the distance each traveled, should be equal
\n" ); document.write( "50*\"13%2F60\" = 10.8 mi
\n" ); document.write( "36*\"18%2F60\" = 10.8 mi
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