document.write( "Question 393818: Tracy leaves for work at 8am, traveling at 36mph. Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. At what time will Sarah catch Tracy? \n" ); document.write( "
Algebra.Com's Answer #279545 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Tracy leaves for work at 8am, traveling at 36mph. \n" ); document.write( " Sarah leaves at 8:05 (going 50mph) to catch her to give her her lunch. \n" ); document.write( " At what time will Sarah catch Tracy? \n" ); document.write( ": \n" ); document.write( "Change 5 min to hr: 5/60 = .0833 hrs \n" ); document.write( ": \n" ); document.write( "Let t = Sarah's travel time \n" ); document.write( "then \n" ); document.write( "(t+.0833) = Tracey's travel time \n" ); document.write( ": \n" ); document.write( "When S catches T they will have traveled the same distance \n" ); document.write( "Write a distance equation: d = speed * time \n" ); document.write( ": \n" ); document.write( "50t = 36(t+.0833) \n" ); document.write( "50t = 36t + 3 \n" ); document.write( "50t - 36t = 3 \n" ); document.write( "14t = 3 \n" ); document.write( "t = \n" ); document.write( "Change to minutes \n" ); document.write( "then \n" ); document.write( "13 + 5 = 18 min is Tracy's travel time who left at 8:00 \n" ); document.write( "S catches T at about 8:18 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check this finding the distance each traveled, should be equal \n" ); document.write( "50* \n" ); document.write( "36* |