document.write( "Question 393756: Completely lost on this question:
\n" ); document.write( "x2-3 x
\n" ); document.write( "---- = --- (That's x(ex)squared minus 3 over 5 x(ex)plus 2 equals x over 5)
\n" ); document.write( "5x+2 5
\n" ); document.write( "I think i have to cross distribute for ex. 5(x2-3) and x(5x+2).
\n" ); document.write( "Is that right? Then what do i do?!
\n" ); document.write( "Please help!
\n" ); document.write( "Thanks!
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Algebra.Com's Answer #279419 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
Completely lost on this question:
\n" ); document.write( "x2-3 x
\n" ); document.write( "---- = --- (That's x(ex)squared minus 3 over 5 x(ex)plus 2 equals x over 5)
\n" ); document.write( "5x+2 5
\n" ); document.write( "I think i have to cross distribute for ex. 5(x2-3) and x(5x+2).
\n" ); document.write( "Is that right? Then what do i do?!
\n" ); document.write( "Please help!
\n" ); document.write( "Thanks!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(x^2 - 3)/(5x + 2) = x/5
\n" ); document.write( "cross multiply
\n" ); document.write( "(x^2 - 3) * 5 = (5x + 2) * x
\n" ); document.write( "distribute 5 on left and x on right
\n" ); document.write( "5x^2 - 15 = 5x^2 + 2x
\n" ); document.write( "bring like terms together
\n" ); document.write( "5x^2 - 5x^2 - 2x = 15
\n" ); document.write( "-2x = 15
\n" ); document.write( "x = -15/2
\n" ); document.write( "check:
\n" ); document.write( "x^2 - 3 = 225/4 - 3 = 225/4 - 12/4 = 213/4
\n" ); document.write( "5x + 2 = -75/2 + 2 = -75/2 + 4/2 = -71/2 = -142/4
\n" ); document.write( "(so that it similar to above line)
\n" ); document.write( "(213/4)/(-142/4) = 213/4 * -4/142 = -213/142 = (3 * -71)/(2 * 71) = -3/2
\n" ); document.write( "x/5 = (-15/2)/5 = -15/2 * 1/5 = -15/10 = -3/2, yes\r
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