document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393714>Question 393714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equations of two lines are 2x – y + 3 = 0 and 4x – 2y – 8 = 0.  Find the horizontal distance and vertical distance between the two lines.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279392 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equations of two lines are 2x – y + 3 = 0 and 4x – 2y – 8 = 0.  Find the horizontal distance and vertical distance between the two lines.<BR>\n" );
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document.write( "2x – y = -3<BR>\n" );
document.write( "2x – y = 4 (2nd eqn divided by 2)<BR>\n" );
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document.write( "y-int of 1st eqn = 3<BR>\n" );
document.write( "y-int of 2nd = -4<BR>\n" );
document.write( "Vertical distance = 7<BR>\n" );
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document.write( "x-int of 1st = -1.5<BR>\n" );
document.write( "x-int of 2nd = 2<BR>\n" );
document.write( "Horiz distance = 3.5\r<BR>\n" );
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