document.write( "Question 393694: Of four consecutive odd numbers the product of the second and the forth exceeds the product of the first and the third by 136. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #279383 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x, (x+2),(x+4),(x+6) represent the four consecutive odd numbers
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document.write( "Question States***Write as we Read
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document.write( "(x+2)(x+6) = x(x+4) + 136
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document.write( "solving for x
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document.write( " x^2 + 8x + 12 = x^2 + 4x + 136
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document.write( "             4x = 124
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document.write( "              x = 31  Number are 31,33,35,37\r
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document.write( "CHECKING our Answer
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document.write( " 33*37 = 31*35 + 136 \n" );
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