document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393679>Question 393679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the tan of angle B on a right triangle when BC equals 5 CA equals 12 and AB equals 13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279362 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio for tangent is opposite over adjacent. Sketching this triangle may help you understand how to do this problem.<br><BR>\n" );
document.write( "Since AB is the longest side it must be the hypotenuse. This makes angle C the right angle. So draw a triangle with C being a right angle and with the sides being the lengths given.<br><BR>\n" );
document.write( "Looking at this triangle you should be able to see that the opposote side for angle B is AC (or 12) and the adjacent side for angle B is BC (or 5) So this makes:<BR>\n" );
document.write( "tan(B) = 5/12 </SPAN>\n" );
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