document.write( "Question 393668: The probability that an employee at the company is over 30 years old is 0.7 if 15 employees are asked their age find the probability that
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document.write( "A) 5 are over 30 years old
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document.write( "B)at least 10 are over 30 years old
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document.write( "C) fewer than 8 are over 30
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document.write( "D)mean
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document.write( "E) variance
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document.write( "F) standard deviation \n" );
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Algebra.Com's Answer #279351 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The probability that an employee at the company is over 30 years old is 0.7 \n" ); document.write( "If 15 employees are asked their age find the probability that \n" ); document.write( "A) 5 are over 30 years old \n" ); document.write( "P(x = 5) = binompdf(15,0.7,5) = 0.0030 \n" ); document.write( "--------------------- \n" ); document.write( "B)at least 10 are over 30 years old \n" ); document.write( "P(10<= x <=15) = 1-binomcdf(15,0.7,9) = 0.7216 \n" ); document.write( "--------------------- \n" ); document.write( "C) fewer than 8 are over 30 \n" ); document.write( "P(0<= x <=7) = binomcdf(15,0.7,7) = 0.0500 \n" ); document.write( "--- \n" ); document.write( "D)mean = np = 15*0.7 \n" ); document.write( "--- \n" ); document.write( "E) variance = npq = 15*0.7*0.3 \n" ); document.write( "--- \n" ); document.write( "F) standard deviation = sqrt(variance) \n" ); document.write( "========================================= \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |