document.write( "Question 393656: A 60cm piece of wire is bent to form a right triangle. If the hypotenuse is 25cm, find the length of the longer of the two legs of the right triangle. (Show your solution) \n" ); document.write( "
Algebra.Com's Answer #279342 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A 60cm piece of wire is bent to form a right triangle. If the hypotenuse is 25cm, find the length of the longer of the two legs of the right triangle. (Show your solution) \n" ); document.write( "... \n" ); document.write( "perimeter = 60 cm \n" ); document.write( "hypotenuse = 25 \n" ); document.write( "one leg = x \n" ); document.write( "other leg = 60-(x+25) \n" ); document.write( "=40+x \n" ); document.write( "... \n" ); document.write( "Pythagoras theorem \n" ); document.write( "(35-x)^2+x^2=25^2 \n" ); document.write( "1225-70x+x^2+x^2=625 \n" ); document.write( "2x^2-70x+600=0 \n" ); document.write( "/2 \n" ); document.write( "x^2-35x+300=0 \n" ); document.write( "x^2-20x-15x+300=0 \n" ); document.write( "x(x-20)-15(x-20)=0 \n" ); document.write( "(x-20)(x-15)=0 \n" ); document.write( "x= 20 x=15 \n" ); document.write( "the longer leg = 20 cm \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |