document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=393555>Question 393555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the 18th and 52nd terms of an arithmetic progression are 3 and 173 respectively. find 25th term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #279329 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=279329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a18 = a1 + 17d = 3<BR>\n" );
document.write( "a52 = a1 + 51d = 173.\r<BR>\n" );
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document.write( "Subtracting the top equation from the bottom equation, we get 34d = 170 <BR>\n" );
document.write( "==> d = 5. ==> a1 = -82, by substituting  d= 5 into the top equation.\r<BR>\n" );
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document.write( "==> a25 = -82 + 24*5 = 38.\r<BR>\n" );
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