document.write( "Question 393625: At present, the sum of the parents' ages is twice the sum of the children's ages. five years ago, the sum of the parents's ages was four times the sum of the children's ages. Fifteen years hence, the sum of the parents' ages will be equal to the sum of the children's ages.How many children are there? \n" ); document.write( "
Algebra.Com's Answer #279326 by mananth(16946)\"\" \"About 
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At present, the sum of the parents' ages is twice the sum of the children's ages. five years ago, the sum of the parents's ages was four times the sum of the children's ages. Fifteen years hence, the sum of the parents' ages will be equal to the sum of the children's ages.How many children are there?
\n" ); document.write( "...
\n" ); document.write( "let number of children be x
\n" ); document.write( "let sum of childrens' age = y
\n" ); document.write( "sum of parents' age = z
\n" ); document.write( "..
\n" ); document.write( "z=2y
\n" ); document.write( "5 years ago
\n" ); document.write( "z-10 = 4(y-5x) ( four times their age 5 years ago.)(x children so less 5x)
\n" ); document.write( "2y-10=4y-20x
\n" ); document.write( "2y-20x=-10
\n" ); document.write( "/2
\n" ); document.write( "y-10x=-5.....................1
\n" ); document.write( "15 years later ( 2 parents so add 30 )
\n" ); document.write( "z+30= 15x+y
\n" ); document.write( "2y+30=15x+y
\n" ); document.write( "15x-y=30......................2
\n" ); document.write( "add both
\n" ); document.write( "5x=25
\n" ); document.write( "/5
\n" ); document.write( "\"%28highlight%28x=+5%29%29\" Number of children
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "15*5-y=30
\n" ); document.write( "75-y=30
\n" ); document.write( "y=70-30
\n" ); document.write( "y=45 sum of childrens' age
\n" ); document.write( "...
\n" ); document.write( "z= 2y = 90 sum of parents' age
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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